Bar, approximation

By joining the points Pp at the base with Ps at the sinister and Pd at the dexter with Pj at the chief of the figure I can construct a bar more quickly.

Point Pp at the base

If b and h are the width and height of the shield and b/3 the bar width, then the angle â of the bar is the arctangent of h/b, the angle ô = 90^o-â is complementary to â, the adjacent side to ô is half the bar width, b/6, and the hypotenuse, horizontal Gules at the base, which determines the position of point Pp is equal to the adjacent side divided by the cosine of ô, that is, b/6 / cosine of ô, which can be approximated by 2b/9 with an error of 2.4%, an error that in heraldic art is admissible.

Point Pd at the dexter

The angle ê = ô = 90^o-â is complementary to â, its opposite side is also half the bar width and the hypotenuse, vertical Vert at the dexter, which determines the position of point Pd is equal to the opposite side divided by the sine of ê, that is, b/6 / sine of ê, which can be approximated by 2h/9 with an error of 2.4%.

Point Pj at the chief

The calculation of its position at the chief is equivalent to that of point Pp with the same approximation of 2b/9, horizontal Gules at the chief.

Point Ps at the sinister

The calculation of its position at the sinister is equivalent to that of point Pd and can be approximated by 2h/9, vertical Vert at the sinister.

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Blazon keywords: Bend sinister.

Style keywords: Freehand and Semi-circular.

Classification: PDF and Schema.

Depending on the author, the counter-cottise is the bar diminished to 1/2 or 1/3 of its width.

Counter-cottise 1/2 of the bar width

If b is the shield width, b/3 that of the bar, then that of the counter-cottise is 1/2 x b/3 = b/6. On a bar I can draw the vertical V1-V2 and divide it by Thales into 4 segments, assigning the 2 central ones to the counter-cottise with sides parallel to the bar. The width of each segment is 1/4 x b/3 = b/12 and the 2 central ones sum b/12 + b/12 = b/6.

Counter-cottise 1/3 of the bar width

If the diminution is to be 1/3 of the bar width, then the counter-cottise width is 1/3 x b/3 = b/9. From the same previous bar I can repeat the process, drawing on the bar the vertical line V1-V2 and dividing it by Thales, in this case, into 3 segments, assigning the central segment to the counter-cottise with sides also parallel to those of its bar.

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Blazon keywords: Bendlet sinister and Bend sinister.

Style keywords: Freehand and Pointed.

Classification: PDF and Schema.

The cottise is the bend diminished to 1/2 or 1/3 of its width, depending on the author.

Cottise 1/2 of the bend width

If the bend width is 1/3 of the shield width b, then that of the cottise is 1/2 x b/3 = b/6. From a bend I can, for example, draw on it the vertical V1-V2 and divide it by Thales into 4 segments, assigning the 2 central ones to the cottise, drawing its sides parallel to the bend. When dividing by 2, an even number, no segment remains centred. Therefore, I divide by 4, double of 2, and group the 2 central segments. The width of each segment is 1/4 x b/3 = b/12 and the 2 central ones sum b/12 + b/12 = b/6.

Cottise 1/3 of the bend width

If the diminution is to 1/3 of the bend width, then the cottise width is 1/3 x b/3 = b/9. From the previous bend I can follow the same process, drawing on the bend the vertical line V1-V2 and dividing it by Thales. In this second case it is divided by 3 which, being odd, leaves one of the segments centred and it is not necessary to divide by double as in the first case. To finish constructing this cottise it suffices to draw through the ends of the central segment 2 lines parallel to the bend of which this cottise is a diminution.

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Blazon keywords: Bendlet and Bend.

Style keywords: Freehand and Pointed.

Classification: PDF and Schema.

Publication of my creation of the arms corresponding to the title Marquess of Casa Portocarrero, Royal House of Georgia, on the blog Twelve Lineages of Soria quoting me as follows: My design and artistic creation of the coat of arms of the Marquess of Casa Portocarrero.

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Categories: Link, Or, Azure, Chequey, Gules, Argent, Bordure, Compony, Dragon, Winged, Couchant and Double queued.

Root: Twelve Lineages of Soria.

There are several methods to draw a pointed coat of arms, for example, the method of [The Heraldry Society; 2013; page 7]. There are also several pointed coat of arms with the ratio 5/6 between its width b and its height h.

The previous illustation shows my method to draw a 5/6 pointed coat of arms. The center Cd of the dexter arc is 17h/36 = 17b/30 from the top of the shield and its radious is 13h/24 = 13b/20, or what is the same, its diameter is 13h/12 = 13b/10.

The position of the Cs of the sinister arc and its construction is symmetric to the dexter arc with respect to the vertical axis, as shown in the following illustration.

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Style keywords: Freehand and Pointed.

Classification: PDF and Schema.

There is a series of nine coats of arms in the ballroom of the castle:

• Or, three Fleurs de lis Azure.
• Azure, a Bendsinister Or.
• Or, a Fleur de lis Azure.
• Azure, a Cross Or.
• Or, five Fleur de lis Azure in saltire.
• Azure, a Fess Or.
• Or, two Fleur de lis Azure in bend.
• Azure, a Saltire Or.
• Or, four Fleur de lis Azure.

There are so many Fleurs de lis that everyone, except the joker, calls it the «fleurdelisée» room. Nobody knows the reason why the joker says there is none, do you?

Think before you move the cursor or click on the following link and see the solution.

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Categories: Riddle, Or, Azure, Fleur de lis, One, Two, Three, Four, Five, Bend sinister, Cross, Fess and Saltire.

Transform the blazon «Or» into «Or, five Pommes in saltire» and the blazon «Argent» into «Argent, five Hurts in saltire» moving the pommes and hurts through both metals, without breaking the rule of tinctures.

You can change one charge by another one, but only once.

For example, if you change «Sable, a Bend Argent» by «Sable, a Pale Argent», then the Pommes can arrive to «Or» blazon. However, this is not a solution, because the Hurts cannot walk to «Argent» blazon.

Think before you move the cursor or click on the following link and see the solution.

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Categories: Riddle, Ogee, Outlined in sable, Freehand, Or, Argent, Vert, Azure, Gules, Sable, Hurt, torteau, pellet, pomme and golpe, Hurt, Pomme, In saltire, Fess, Saltire, Bend sinister, Cross, Pale and Bend.

Gules, three Clarions Or.

Plain tinctures and parchment finishing.

This wind musical instrument appears at [Académie internationale d'héraldique; 1952; figura 476] as «claricord» and also «clarion», I like more this second name.

The clarion is also called «clarichord», «sufflue» or «rest». Then other alternative blazons for this coat of arms could be «Gules, three Claricords Or», «Gules, three Clarichords Or» or «Gules, three Sufflues Or».

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Blazon keywords: Without divisions, Gules, Three, Clarion and Or.

Style keywords: Parchment, Outlined in sable and Plain tincture.

Classification: Interpreted and Kingdom of England.

Bearer: Grenville, Thomas.

Continue with: Grenville, Thomas.